Mr \(\ce{H2SO4}\) = 2 + 32 + 64 = 98

Massa zat terlarut (asam sulfat) = 0,98 gram

Mr \(\ce{H2O}\) = 2 + 16 = 18

Massa pelarut (air) = 250 gram

\(m = \dfrac{\text{massa zat terlarut}}{\text{Mr}} \times \dfrac{1000}{\text{massa pelarut (gram)}}\)

\(m = \dfrac{0,98}{98} \times \dfrac{1000}{250}\)

\(m = \dfrac{1}{100} \times \dfrac{1000}{250}\)

\(m = \dfrac{10}{250}\)

\(m = \dfrac{1}{25}\)

\(m = 0,04 \text{ m}\)

Mr \((\ce {C2H5OH})\) = 24 + 5 + 16 + 1 = 46

Massa etanol = 46 gram

Massa air = 100 − 46 = 54 gram

\(m = \dfrac{46}{46} \times \dfrac{1000}{54}\)

\(m = 1 \times \dfrac{1000}{54}\)

\(m = 18,52 \text{ m}\)