Latihan Pecahan 02

Jawaban: B

Kerjakan penjumlahan di dalam kurung terlebih dahulu,

\(\dfrac{11}{15} \: – \: (\dfrac{1}{5} + \dfrac{2}{5})\)

\(\dfrac{11}{15} \: –  \:\dfrac{3}{5}\:\:\:\:\:\color{blue}\text{samakan penyebut}\)

\(\dfrac{11}{15} \: – \: \dfrac{9}{15}\)

\(\dfrac{2}{15}\)

Jawaban: A

\(20\% = \dfrac{20}{100}\)

Sederhanakan pecahan \(\dfrac{20}{100}\)

\(\dfrac{20}{100} = \dfrac{20 \div \color{red}20}{100 \div \color{red}20} = \dfrac{1}{5}\)

Jawaban: D

Jumlahkah terlebih dahulu 13,215 dan 4,50

\begin{equation*}
\begin{split}
13&,215\\\\
4&,500\\
——&—— \:\:\:\color{blue}(+)\\
17&,715
\end{split}
\end{equation*}

Selanjutnya, kurangkan 17,715 dengan 1,2

\begin{equation*}
\begin{split}
17&,715\\\\
1&,200\\
——&—— \:\:\:\color{blue}(-)\\
16&,515
\end{split}
\end{equation*}

Jadi \(13,215 + 4,50 \:-\: 1,2 = 16,515\)

Jawaban: A

Ubah \(55\%\) dan \(\dfrac{2}{5}\) menjadi pecahan desimal

\(55\% = \dfrac{55}{100} = 0,55\)

\(\dfrac{2}{5} = 0,4\)

Kurangkan 0,55 dengan 0,4

\begin{equation*}
\begin{split}
0&,55\\\\
0&,40\\
—&— \:\:\:\color{blue}(-)\\
0&,15
\end{split}
\end{equation*}

Selanjutnya, jumlahkan 0,15 dengan 0,05

\begin{equation*}
\begin{split}
0&,15\\\\
0&,05\\
—&— \:\:\:\color{blue}(+)\\
0&,20
\end{split}
\end{equation*}

Jadi, \(55\%\:-\: \dfrac{2}{5} + 0,05 = 0,20\)

Jawaban: A

Kerjakan penjumlahan pecahan dahulu,

\(\color{blue}(1\dfrac{2}{5} + 3\dfrac{1}{5})\color{black}\:-\: 2\dfrac{3}{5}\)

\(\color{blue}(1 + 3 + \dfrac{2}{5} + \dfrac{1}{5})\color{black} \:-\: 2\dfrac{3}{5}\)

\(\color{blue}(4 + \dfrac{3}{5})\color{black}\:-\: 2\dfrac{3}{5}\)

\(4 + \dfrac{3}{5}\:-\: 2\:-\:\dfrac{3}{5}\)

\(4 \:-\: 2 + \dfrac{3}{5}\:-\:\dfrac{3}{5}\)

\(2 + 0\)

\(2\)

Jawaban: C

Kerjakan pengurangan pecahan terlebih dahulu,

\(\color{blue}(3\dfrac{4}{7} \:-\: 2\dfrac{1}{2})\color{black} + 5\dfrac{1}{14}\)

\(\color{blue}(3 + \dfrac{4}{7} \:-\: 2\: – \:\dfrac{1}{2})\color{black} + 5\dfrac{1}{14}\)

\(\color{blue}(3 \:-\: 2 + \dfrac{4}{7} \:-\: \dfrac{1}{2})\color{black} + 5\dfrac{1}{14}\)

\(\color{blue}(1 + \dfrac{8}{14} \:-\: \dfrac{7}{14})\color{black}+ 5 + \dfrac{1}{14}\)

\(1 + \dfrac{1}{14}+ 5 + \dfrac{1}{14}\)

\(1 + 5 + \dfrac{1}{14}+\dfrac{1}{14}\)

\(6 + \dfrac{2}{14}\:\:\:\:\:\color{blue}\text{sederhanakan}\)

\(6 + \dfrac{1}{7}\)

\(6\dfrac{1}{7}\)

Jawaban: B

Ubah menjadi pecahan desimal

\(\dfrac{5}{8} = 0,625\)

\(63\% = \dfrac{63}{100} = 0,630\:\:\:\:\color{blue}\text{terbesar}\)

Jadi \(\dfrac{5}{8}\:<\: 63\%\)

Jawaban: B

Ubah dalam bentuk pecahan desimal:

\(\dfrac{5}{6} \approx 0,83\)

\(0,82 = 0,82\:\:\:\:\:\color{blue}\text{terkecil}\)

\(84\% = \dfrac{84}{100} = 0,84\)

\(\dfrac{9}{10} = 0,90\:\:\:\:\:\color{blue}\text{terbesar}\)

Jadi, urutan pecahan dari yang terbesar sampai terkecil adalah:

\(\dfrac{9}{10};\:\:\: 84\%;\:\:\: \dfrac{5}{6};\:\:\:0,82\)

Jawaban: D

Ubah dalam bentuk pecahan desimal:

\(3\dfrac{5}{8} = 3 + \dfrac{5}{8} = 3 + 0,625 = 3,625\)

\(3,630 = 3,630\:\:\:\:\:\color{blue}\text{terbesar}\)

\(320\% = \dfrac{320}{100} = 3,20\:\:\:\:\:\color{blue}\text{terkecil}\)

\(\dfrac{39}{12} = 3\dfrac{3}{12} = 3 + \dfrac{1}{4} = 3 + 0,25 = 3,25\)

Jadi, urutan pecahan dari yang terkecil sampai terbesar adalah:

\(320\%;\:\:\: \dfrac{39}{12};\:\:\: 3\dfrac{5}{8};\:\:\:3,630\)

Jawaban: A

Ubah 250 gram dalam satuan kg, perlu diingat bahwa 1 gram setara dengan \(\dfrac{1}{1000}\) kg

Jadi 250 gram = \(\dfrac{250}{1000} = \dfrac{250 \div \color{red} 250}{1000 \div \color{red} 250} = \dfrac{1}{4}\text{ kg}\)

Persediaan gula ibu sekarang = \(\dfrac{3}{4}\) kg − \(\dfrac{2}{5}\) kg + \(\dfrac{1}{4}\) kg  (samakan penyebut)

Persediaan gula ibu sekarang = \(\dfrac{15}{20}\) kg − \(\dfrac{8}{20}\) kg + \(\dfrac{5}{20}\) kg

Persediaan gula ibu sekarang = \(\dfrac{15\:-\:8 + 5}{20} = \dfrac{12}{20} = \dfrac{3}{5}\) kg