Vektor 3 Dimensi

Perhatikan gambar kubus ABCD.EFGH berikut:

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Diketahui kubus ABCD.EFGH memiliki rusuk dengan panjang 10 satuan.

  • \(\overrightarrow{\text{DA}}= 10\textbf{i} \text{ dan } \overrightarrow{\text{AD}}= -10\textbf{i} \)
  • \(\overrightarrow{\text{DC}}= 10\textbf{j} \text{ dan } \overrightarrow{\text{CD}}= -10\textbf{j} \)
  • \(\overrightarrow{\text{DH}}= 10\textbf{k} \text{ dan } \overrightarrow{\text{HD}}= -10\textbf{k} \)

Dari informasi di atas, nyatakan:

A.  Vektor \(\overrightarrow{\text{DB}}\) dan panjang DB

B.  Vektor\(\overrightarrow{\text{DF}}\) dan panjang DF

C.  Vektor \(\overrightarrow{\text{AC}}\) dan panjang AC

D.  Vektor \(\overrightarrow{\text{AG}}\) dan panjang AG

 

Penyelesaian:

 

Menyatakan vektor \(\overrightarrow{\text{DB}}\)

\(\overrightarrow{\text{DB}} = \overrightarrow{\text{DA}} + \overrightarrow{\text{AB}}\)

\(\overrightarrow{\text{DB}} = 10\textbf{i} + 10\textbf{j}\)

\(\text{DB} = \sqrt{10^2 + 10^2} = \sqrt{200} = 10\sqrt{2}\text{ satuan}\)

 

Menyatakan vektor \(\overrightarrow{\text{DF}}\)

\(\overrightarrow{\text{DF}} = \overrightarrow{\text{DB}} + \overrightarrow{\text{BF}}\)

\(\overrightarrow{\text{DF}} = 10\textbf{i} + 10\textbf{j} + 10\textbf{k}\)

\(\text{DF} = \sqrt{10^2 + 10^2 + 10^2} = \sqrt{300} = 10\sqrt{3}\text{ satuan}\)

 

Menyatakan vektor \(\overrightarrow{\text{AC}}\)

\(\overrightarrow{\text{AC}} = \overrightarrow{\text{AB}} + \overrightarrow{\text{BC}}\)

\(\overrightarrow{\text{AC}} = 10\textbf{j} \:-\: 10\textbf{i}\)

\(\text{AC} = \sqrt{10^2 + (-10)^2} = \sqrt{200} = 10\sqrt{2}\text{ satuan}\)

 

Menyatakan vektor \(\overrightarrow{\text{AG}}\)

\(\overrightarrow{\text{AG}} = \overrightarrow{\text{AC}} + \overrightarrow{\text{CG}}\)

\(\overrightarrow{\text{AG}} = 10\textbf{j} \:-\: 10\textbf{i} + 10\textbf{k}\)

\(\text{AG} = \sqrt{10^2 + (-10)^2 + 10^2} = \sqrt{300} = 10\sqrt{3}\text{ satuan}\)

 

Contoh Soal

 

Soal 1

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Kubus ABCD.EFGH memiliki panjang rusuk 10 satuan. Titik P terletak di tengah HG. Tentukan panjang AP.

 

 

Soal 2

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Kubus ABCD.EFGH memiliki panjang rusuk 10 satuan. Titik P terletak pada EF dengan perbandingan EP : PF = 2 : 3. Titik Q terletak pada CG dengan perbandingan CQ : QG = 1 : 4. Tentukan panjang PQ.