Penjumlahan dan pengurangan pecahan yang penyebutnya sudah sama
Contoh:
- \(\dfrac{2}{5} + \dfrac{1}{5} = \dfrac{2 + 1}{5} = \dfrac{3}{5}\)
- \(\dfrac{5}{13} – \dfrac{2}{13} = \dfrac{5-2}{13} = \dfrac{3}{13}\)
- \(\dfrac{4}{9} + \dfrac{2}{9} – \dfrac{1}{9} = \dfrac{4 + 2 – 1}{9} = \dfrac{5}{9}\)
Hitunglah!
(1) \(\dfrac{3}{7} + \dfrac{1}{7}\)
\(\color{purple} \dfrac{3}{7} + \dfrac{1}{7} = \dfrac{3 + 1}{7} = \dfrac{4}{7}\)
(2) \(\dfrac{5}{8} + \dfrac{3}{8}\)
\(\color{purple} \dfrac{5}{8} + \dfrac{3}{8}=\dfrac{5+3}{8} = \dfrac{8}{8}=1\)
(3) \(\dfrac{4}{13} – \dfrac{3}{13}\)
\(\color{purple} \dfrac{4}{13} – \dfrac{3}{13} = \dfrac{4-3}{13} = \dfrac{1}{13}\)
(4) \(\dfrac{8}{15} – \dfrac{4}{15}\)
\(\color{purple} \dfrac{8}{15} – \dfrac{4}{15} = \dfrac{8 – 4}{15} = \dfrac{4}{15}\)
(5) \(\dfrac{2}{7} +\dfrac{4}{7}-\dfrac{1}{7}\)
\(\color{purple}\dfrac{2}{7} +\dfrac{4}{7}-\dfrac{1}{7} = \dfrac{2 + 4 – 1}{7} = \dfrac{5}{7}\)
(6) \(\dfrac{5}{9} -\dfrac{3}{9}+\dfrac{1}{9}\)
\(\color{purple}\dfrac{5}{9} -\dfrac{3}{9}+\dfrac{1}{9} = \dfrac{5-3+1}{9} = \dfrac{3}{9}\)
(7) \(\dfrac{11}{13} -\dfrac{2}{13}-\dfrac{3}{13}\)
\(\color{purple}\dfrac{11}{13} -\dfrac{2}{13}-\dfrac{3}{13} = \dfrac{11-2-3}{13} = \dfrac{6}{13}\)
(8) \(\dfrac{15}{19} -\dfrac{5}{19}-\dfrac{6}{19}\)
\(\color{purple}\dfrac{15}{19} -\dfrac{5}{19}-\dfrac{6}{19} = \dfrac{15-5-6}{19} = \dfrac{4}{19}\)
Penjumlahan dan pengurangan pecahan yang penyebutnya belum sama
Contoh 1
\(\dfrac{1}{3} + \dfrac{1}{2}\)
Untuk menyamakan penyebut, carilah nilai KPK (Kelipatan Persekutuan Terkecil) dari 3 dan 2
KPK dari 3 dan 2 adalah 6
Selanjutnya, tulis dalam bentuk penjumlahan pecahan senilainya
\(\dfrac{1}{3} + \dfrac{1}{2} = \dfrac{2}{6} + \dfrac{3}{6}\)
\(\dfrac{1}{3} + \dfrac{1}{2} = \dfrac{2+3}{6}\)
\(\dfrac{1}{3} + \dfrac{1}{2} = \dfrac{5}{6}\)
Contoh 2
\(\dfrac{2}{5} – \dfrac{1}{3}\)
Untuk menyamakan penyebut, carilah nilai KPK (Kelipatan Persekutuan Terkecil) dari 5 dan 3
KPK dari 5 dan 3 adalah 15
Selanjutnya, tulis dalam bentuk penjumlahan pecahan senilainya
\(\dfrac{2}{5} – \dfrac{1}{3} = \dfrac{6}{15} – \dfrac{5}{15}\)
\(\dfrac{2}{5} – \dfrac{1}{3} = \dfrac{6-5}{15}\)
\(\dfrac{2}{5} – \dfrac{1}{3} = \dfrac{1}{15}\)
Contoh 3
\(\dfrac{1}{3} + \dfrac{1}{2} – \dfrac{1}{6}\)
Untuk menyamakan penyebut, carilah nilai KPK (Kelipatan Persekutuan Terkecil) dari 3, 2, dan 6
KPK dari 3, 2, dan 6 adalah 6
Selanjutnya, tulis dalam bentuk penjumlahan pecahan senilainya
\(\dfrac{1}{3} + \dfrac{1}{2} – \dfrac{1}{6} = \dfrac{2}{6} + \dfrac{3}{6} – \dfrac{1}{6}\)
\(\dfrac{1}{3} + \dfrac{1}{2} – \dfrac{1}{6} = \dfrac{2+3-1}{6}\)
\(\dfrac{1}{3} + \dfrac{1}{2} – \dfrac{1}{6} = \dfrac{4}{6}\)
\(\dfrac{1}{3} + \dfrac{1}{2} – \dfrac{1}{6} = \dfrac{2}{3}\)
Hitunglah!
(1) \(\dfrac{2}{5} + \dfrac{1}{4}\)
\(\color{purple}\dfrac{2}{5} + \dfrac{1}{4} = \dfrac{8}{20} + \dfrac{5}{20} = \dfrac{13}{20}\)
(2) \(\dfrac{1}{7} + \dfrac{2}{3}\)
\(\color{purple}\dfrac{1}{7} + \dfrac{2}{3} = \dfrac{3}{21} + \dfrac{14}{21} = \dfrac{17}{21}\)
(3) \(\dfrac{5}{12} + \dfrac{1}{6}\)
\(\color{purple}\dfrac{5}{12} + \dfrac{1}{6} = \dfrac{5}{12} + \dfrac{2}{12} = \dfrac{7}{12}\)
(4) \(\dfrac{2}{3} + \dfrac{5}{18}\)
\(\color{purple}\dfrac{2}{3} + \dfrac{5}{18} = \dfrac{12}{18} + \dfrac{5}{18} = \dfrac{17}{18}\)
(5) \(\dfrac{3}{4} – \dfrac{1}{2}\)
\(\color{purple}\dfrac{3}{4} – \dfrac{1}{2} = \dfrac{3}{4} – \dfrac{2}{4} = \dfrac{1}{4}\)
(6) \(\dfrac{5}{7} – \dfrac{1}{5}\)
\(\color{purple}\dfrac{5}{7} – \dfrac{1}{5} = \dfrac{25}{35} – \dfrac{7}{35} = \dfrac{18}{35}\)
(7) \(\dfrac{4}{5} – \dfrac{2}{3}\)
\(\color{purple}\dfrac{4}{5} – \dfrac{2}{3} = \dfrac{12}{15} – \dfrac{10}{15} = \dfrac{2}{15}\)
(8) \(\dfrac{6}{7} – \dfrac{4}{5} +\dfrac{2}{35}\)
\(\color{purple}\dfrac{6}{7} – \dfrac{4}{5} +\dfrac{2}{35} = \dfrac{30}{35} – \dfrac{28}{35} +\dfrac{2}{35} = \dfrac{4}{35}\)
(9) \(\dfrac{2}{3} +\dfrac{1}{2} -\dfrac{5}{12}\)
\(\color{purple}\dfrac{2}{3} +\dfrac{1}{2} -\dfrac{5}{12} = \dfrac{8}{12} + \dfrac{6}{12} -\dfrac{5}{12} = \dfrac{9}{12} = \dfrac{3}{4}\)
(10) \(\dfrac{5}{6} -\dfrac{1}{3} -\dfrac{1}{2}\)
\(\color{purple}\dfrac{5}{6} -\dfrac{1}{3} -\dfrac{1}{2} = \dfrac{10}{12} -\dfrac{4}{12} -\dfrac{6}{12} = \dfrac{0}{12} = 0\)